+15 votes
by (100 points)
Determine the voltage drop from the top terminal to the bottom terminal, vab, in the right hand branch and, vcd, in the left hand branch of the circuit. Determine each voltage drop based on the elements in the corresponding branch.

1 Answer

0 votes
by (100 points)
Hello your question is incomplete attached below is the missing part of the questionanswer ; voltage drop in the Vcd branch = 30 V Voltage drop in the middle branch = 40v - 30v = 10 volts voltage drop in AB = 60 + ( -600 * 0.05 ) = 60 - 30 = 30 voltsExplanation:Determine voltage drop from top terminal to bottom terminal ( Vab ) in the right hand branch and Vcd in left hand branch 40v and 50mA are in series hence;  Ix = 50mAalso Vcd = 30V CD is parallel to AB hence; Vcd = Vab = 30 V Vab = ∝*Ix + 60 v  30v  = ∝ ( 50mA ) + 60 therefore ∝ = -600 voltage drop in the Vcd branch = 30 V Voltage drop in the middle branch = 40v - 30v = 10 volts voltage drop in AB = 60 + ( -600 * 0.05 ) = 60 - 30 = 30 volts
Welcome to Answerscourse Q&A, where you can ask questions and receive answers from other members of the community.
...