â€¢Estimated density = 39.685Pc/mi/enâ€¢Level of service, LOS frequency = LOSCExplanation:We are given:â€¢Freeway current lane width,B = 12ftâ€¢ freeway current shoulder width,b = 6ftâ€¢ percentage of heavy vehicle, Ptb = 10â„…â€¢ peak hour factor, PHF = 0.9Let's consider,â€¢Number of lanes N = 4â€¢ flow of traffic V = 7500vphâ€¢ percentage of Rv = 0, therefore the freeflow speed in freeway FFS = 70mphâ€¢ cars equivalent for recreational purpose Er= 2â€¢cars to be used for trucks and busses Etb= 2.5Let's first calculate for the heavy adjustment factor.We have:Substituting figures in the equation we have:= 0.75Let's now calculate equivalent flow rate of the car using:= 2777.7 pc/h/enCalculating for traffic density, we have:D = 39.685 Pc/mi/enUsing the table for LOS criteria of basic frequency segment, the level of service LOS of frequency is LOSC